Http传输json进行服务端接口与客户端对接，以及restful实现

妖狐艹你老母 2022-05-16 13:46 329阅读 0赞

原文地址：[https://blog.csdn.net/u011320740/article/details/53537484][https_blog.csdn.net_u011320740_article_details_53537484]

话不多说，直接贴代码，照写就好了

服务端接口编写，我用的是springmvc,服务端接口其实和平时web开发一样，就是返回出json就好了，还有就是接受数据也是json，方法如下：

@Controller
    
    @RequestMapping("/user")
    
    public class UserController {
    
    
    @Autowired
    
    private UserService userservice;
    
    @RequestMapping("/getUserByName")
    
    public @ResponseBody User getUserByName(HttpServletRequest request) throws IOException{
    
    StringBuffer str = new StringBuffer();
    
    try {
    
    BufferedInputStream in = new BufferedInputStream(request.getInputStream());
    
    int i;
    
    char c;
    
    while ((i=in.read())!=-1) {
    
    c=(char)i;
    
    str.append(c);
    
    }
    
    }catch (Exception ex) {
    
    ex.printStackTrace();
    
    }
    
    JSONObject obj= JSONObject.fromObject(str.toString());
    
    System.out.println(obj.get("name"));
    
    User user= userservice.getUserByName(obj.get("name").toString());
    
    return user;
    
    }
    
    
    }

实现的是一个通过服务端接收客户端json\{“name”:"cwh"\}名字name进行查询操作，然后给客户端返回json;

客户端实现如下：

import java.io.IOException;
    
    
    import net.sf.json.JSONObject;
    
    import net.spring.model.User;
    
    
    import org.apache.http.HttpResponse;
    
    import org.apache.http.client.ClientProtocolException;
    
    import org.apache.http.client.HttpClient;
    
    import org.apache.http.client.methods.HttpPost;
    
    import org.apache.http.entity.StringEntity;
    
    import org.apache.http.impl.client.DefaultHttpClient;
    
    import org.apache.http.util.EntityUtils;
    
    import org.junit.Test;
    
    
    public class Client {
    
    @Test
    
    public void HttpPostData() {
    
    try {
    
    HttpClient httpclient = new DefaultHttpClient();
    
    String uri = "http://localhost:8080/springMVC/user/getUserByName";
    
    HttpPost httppost = new HttpPost(uri);
    
    //添加http头信息
    
    httppost.addHeader("Authorization", "your token"); //认证token
    
    httppost.addHeader("Content-Type", "application/json");
    
    httppost.addHeader("User-Agent", "imgfornote");
    
    JSONObject obj = new JSONObject();
    
    obj.put("name", "cwh");
    
    httppost.setEntity(new StringEntity(obj.toString()));
    
    HttpResponse response;
    
    response = httpclient.execute(httppost);
    
    //检验状态码，如果成功接收数据
    
    int code = response.getStatusLine().getStatusCode();
    
    System.out.println(code+"code");
    
    if (code == 200) {
    
    String rev = EntityUtils.toString(response.getEntity());//返回json格式： {"id": "","name": ""}
    
    obj= JSONObject.fromObject(rev);
    
    
    User user = (User)JSONObject.toBean(obj,User.class);
    
    System.out.println("返回数据==="+user.toString());
    
    }
    
    } catch (ClientProtocolException e) {
    
    e.printStackTrace();
    
    } catch (IOException e) {
    
    e.printStackTrace();
    
    } catch (Exception e) {
    
    e.printStackTrace();
    
    }
    
    }
    
    }

ok,把服务端部署到tomcat

运行客户端：返回数据成功

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当然也可以用RESTFUL风格来实现

服务端可以这么编写：

@RequestMapping("/getUserByName/{name}")
    
    public @ResponseBody User getUserByName(@PathVariable("name")String name) throws IOException{
    
    User user= userservice.getUserByName(name);
    
    return user;
    
    }

那么客户端请求就这么写了：

public void HttpPostData() {
    
    try {
    
    HttpClient httpclient = new DefaultHttpClient();
    
    String uri = "http://localhost:8080/springMVC/user/getUserByName/cwh";
    
    HttpPost httppost = new HttpPost(uri);
    
    JSONObject obj = new JSONObject();
    
    
    HttpResponse response;
    
    response = httpclient.execute(httppost);
    
    //检验状态码，如果成功接收数据
    
    int code = response.getStatusLine().getStatusCode();
    
    System.out.println(code+"code");
    
    if (code == 200) {
    
    String rev = EntityUtils.toString(response.getEntity());//返回json格式： {"id": "","name": ""}
    
    obj= JSONObject.fromObject(rev);
    
    User user = (User)JSONObject.toBean(obj,User.class);
    
    System.out.println("返回数据==="+user.toString());
    
    }
    
    } catch (ClientProtocolException e) {
    
    e.printStackTrace();
    
    } catch (IOException e) {
    
    e.printStackTrace();
    
    } catch (Exception e) {
    
    e.printStackTrace();
    
    }
    
    }

这样也是可以的

![Center 1][]

[https_blog.csdn.net_u011320740_article_details_53537484]: https://blog.csdn.net/u011320740/article/details/53537484
[Center]: /images/20220516/7821ab6f006a45e89286bd538947df33.png
[Center 1]: /images/20220516/f738051d5ee84a67858a90d98b96571f.png