获取线程返回结果

谁借莪１个温暖的怀抱￠ 2022-05-13 14:08 199阅读 0赞

public class MyTest {
        private static final ListeningExecutorService service = MoreExecutors.listeningDecorator(newFixedThreadPool(10));
        private static final Collection<Future<?>> futures = new LinkedList<>();
    
        public static void main(String[] args) throws IOException {
            List<String> list = new ArrayList<>();
            list.add("1");
            list.add("2");
            list.add("0");
            list.add("0");
            list.add("0");
            list.add("0");
            for (final String str : list) {
                ListenableFuture<Integer> explosion = service.submit(() -> {
                    try {
                        if (str.equals("0")) {
                            return 0;
                        }
                        return 1;
                    } catch (Exception e) {
                    }
                    return 1;
                });
                futures.add(explosion);
                Futures.addCallback(explosion, new FutureCallback<Integer>() {
    
                    @Override
                    public void onSuccess(Integer num) {
                        if (num == 0) {
                            System.out.println("是0了");
                        } else {
                            System.out.println("不是0了");
                        }
                    }
    
                    @Override
                    public void onFailure(Throwable throwable) {
                        System.out.println("线程异常");
                    }
                }, MoreExecutors.directExecutor());
            }
            // 线程等待。
            for (Future<?> future : futures) {
                try {
                    future.get();
                    System.out.println("线程等待");
                } catch (Exception e) {
                    System.out.println("线程等待异常");
                }
            }
    
        }
    }