C语言计算矩阵(二维数组)

古城微笑少年丶 2022-04-24 04:04 400阅读 0赞

![20190414231912377.png][]

![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDExOTUxNw_size_16_color_FFFFFF_t_70][]     ![watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDExOTUxNw_size_16_color_FFFFFF_t_70 1][]

#include<stdio.h>
    #include<stdlib.h>
    main()
    {
        int i,j,k,N,M;
        printf("\t\t矩阵的加减法运算\n");
        printf("你要输入几行的矩阵");
    	scanf("%d",&N);
        printf("\n你要输入几列的矩阵");
        scanf("%d",&M);
        system("cls");
    	printf("\n请你输入矩阵A(%d行%d列)\n",M,N);
    	int A_1[M][N],B_1[M][N];
        for(i=0;i<M;i++)
        {
        	for(j=0;j<N;j++)
            scanf("%d",&A_1[i][j]);
    	}
    	printf("\n请你输入矩阵B(%d行%d列)\n",M,N);
    	for(i=0;i<M;i++)
        {
        	for(j=0;j<N;j++)
        	scanf("%d",&B_1[i][j]);
        }
        printf("\n你要计算矩阵之和还是差(和:1/差:2)\n"); 
    	scanf("%d",&k);
    	while (k!=1&&k!=2)
    	    {
    	    	system("cls"); 
    	    	printf("很抱歉，你输入有误!!!\n请你输入(和:1/差:2)\n");
    	    	scanf("%d",&k);
           }
           switch(k)
        	{
    		case 1 : 
    		    printf("矩阵A和矩阵B之和为:\n");
                for(i=0;i<M;i++)
            {
        	    for(j=0;j<N;j++)
        	    {
        		    A_1[i][j]+=B_1[i][j];
        		    printf("% d\t",A_1[i][j]);
        		
    	     	}
    			printf("\n");
            }return 0; 
            case 2:
            	printf("矩阵A和矩阵B之差为:\n");
                for(i=0;i<M;i++)
            {
        	    for(j=0;j<N;j++)
        	    {
        		    A_1[i][j]-=B_1[i][j];
        		    printf("% d\t",A_1[i][j]);
        		
    	     	}
    			printf("\n");
            	
        	} return 0;
        	} 
    }

[20190414231912377.png]: /images/20220220/cfba1599b93846e9acbf97ebd3f75cbb.png
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[watermark_type_ZmFuZ3poZW5naGVpdGk_shadow_10_text_aHR0cHM6Ly9ibG9nLmNzZG4ubmV0L3dlaXhpbl80NDExOTUxNw_size_16_color_FFFFFF_t_70 1]: /images/20220220/ef0e7db3398b4207a23afa7dcb514c49.png