解析json数据，list转jsonObject再转为string类型

小灰灰 2022-04-23 05:38 728阅读 0赞

1.数据嵌套层级比较深，包含list集合

/**
     * Wrap an object, if necessary. If the object is null, return the NULL
     * object. If it is an array or collection, wrap it in a JSONArray. If it is
     * a map, wrap it in a JSONObject. If it is a standard property (Double,
     * String, et al) then it is already wrapped. Otherwise, if it comes from
     * one of the java packages, turn it into a string. And if it doesn't, try
     * to wrap it in a JSONObject. If the wrapping fails, then null is returned.
     *
     * @param object
     *            The object to wrap
     * @return The wrapped value
     */
    public static Object wrap(Object object) {
        try {
            if (object == null) {
                return NULL;
            }
            if (object instanceof JSONObject || object instanceof JSONArray
                    || NULL.equals(object) || object instanceof JSONString
                    || object instanceof Byte || object instanceof Character
                    || object instanceof Short || object instanceof Integer
                    || object instanceof Long || object instanceof Boolean
                    || object instanceof Float || object instanceof Double
                    || object instanceof String || object instanceof BigInteger
                    || object instanceof BigDecimal) {
                return object;
            }
    
            if (object instanceof Collection) {
                Collection<?> coll = (Collection<?>) object;
                return new JSONArray(coll);
            }
            if (object.getClass().isArray()) {
                return new JSONArray(object);
            }
            if (object instanceof Map) {
                Map<?, ?> map = (Map<?, ?>) object;
                return new JSONObject(map);
            }
            Package objectPackage = object.getClass().getPackage();
            String objectPackageName = objectPackage != null ? objectPackage
                    .getName() : "";
            if (objectPackageName.startsWith("java.")
                    || objectPackageName.startsWith("javax.")
                    || object.getClass().getClassLoader() == null) {
                return object.toString();
            }
            return new JSONObject(object);
        } catch (Exception exception) {
            return null;
        }
    }

这里主要用到wrap方法，实现如上：
    在把list转换为对应的jsonObject后再转换为string的方法就是valueToString了
    org.json.JSONObject.valueToString(org.json.JSONObject.wrap(team.getTdmxList()));