如何实现大整数相加？@漫画

短命女 2022-04-14 05:12 248阅读 0赞

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/\*\* \* 大整数求和 \* @param bigNumberA 大整数A \* @param bigNumberB 大整数B \*/public static String bigNumberSum(String bigNumberA, String bigNumberB) \{ //1.把两个大整数用数组逆序存储，数组长度等于较大整数位数+1 int maxLength = bigNumberA.length() > bigNumberB.length() ? bigNumberA.length() : bigNumberB.length(); int\[\] arrayA = new int\[maxLength+1\]; for(int i=0; i< bigNumberA.length(); i++)\{ arrayA\[i\] = bigNumberA.charAt(bigNumberA.length()-1-i) - ‘0’; \} int\[\] arrayB = new int\[maxLength+1\]; for(int i=0; i< bigNumberB.length(); i++)\{ arrayB\[i\] = bigNumberB.charAt(bigNumberB.length()-1-i) - ‘0’; \} //2.构建result数组，数组长度等于较大整数位数+1 int\[\] result = new int\[maxLength+1\]; //3.遍历数组，按位相加 for(int i=0; i<result.length; i++)\{ int temp = result\[i\]; temp += arrayA\[i\]; temp += arrayB\[i\]; //判断是否进位 if(temp >= 10)\{ temp = temp-10; result\[i+1\] = 1; \} result\[i\] = temp; \} //4.把result数组再次逆序并转成String StringBuilder sb = new StringBuilder(); //是否找到大整数的最高有效位 boolean findFirst = false; for (int i = result.length - 1; i >= 0; i–) \{ if(!findFirst)\{ if(result\[i\] == 0)\{ continue; \} findFirst = true; \} sb.append(result\[i\]); \} return sb.toString();\}public static void main(String\[\] args) \{ System.out.println(bigNumberSum(“426709752318”, “95481253129”));\}

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