[LeetCode] Path Sum 二叉树的路径和

àì夳堔傛蜴生んèń 2022-04-14 04:53 185阅读 0赞

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Given the below binary tree and `sum = 22`,

5
                 / \
                4   8
               /   / \
              11  13  4
             /  \      \
            7    2      1

return true, as there exist a root-to-leaf path `5->4->11->2` which sum is 22.

/// 112. Path Sum
    /// https://leetcode.com/problems/path-sum/description/
    /// 时间复杂度: O(n), n为树的节点个数
    /// 空间复杂度: O(h), h为树的高度
    class Solution {
    
        // Definition for a binary tree node.
        public class TreeNode {
            int val;
            TreeNode left;
            TreeNode right;
            TreeNode(int x) { val = x; }
        }
    
        public boolean hasPathSum(TreeNode root, int sum) {
    
            if(root == null)
                return false;
    
            if(root.left == null && root.right == null)
                return sum == root.val;
    
            return hasPathSum(root.left, sum - root.val)
                    || hasPathSum(root.right, sum - root.val);
        }
    }

类似问题:

1. 404sum of left leaves

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