使用python测测你的系统最多能创建多少个线程

冷不防 2022-04-05 07:18 218阅读 0赞

2012-12-09 08:27:00      [我来说两句 ][Link 1]      作者：iihero

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使用一个循环，不断的创建线程，直到出现异常，才通知它们。python真是个好东西。  
代码如下：  
\#!/usr/bin/env python  
\#coding=gbk

import threading  
import time, random,  sys

class Counter:  
    def \_\_init\_\_(self):  
        self.lock = threading.Lock()  
        self.value = 0

def increment(self):  
        self.lock.acquire()  
        self.value = value = self.value + 1  
        self.lock.release()  
        return value

counter = Counter()  
cond = threading.Condition()

class Worker(threading.Thread):

def run(self):  
        print self.getName(),  "-- created."  
        cond.acquire()  
        \#for i in range(10):  
            \# pretend we're doing something that takes 10?00 ms  
            \#value = counter.increment()  
            \# time.sleep(random.randint(10, 100) / 1000.0)  
        cond.wait()  
        \#print self.getName(), "-- task", "finished"  
        cond.release()

if \_\_name\_\_ == '\_\_main\_\_':  
     
        try:  
            for i in range(3500):  
                Worker().start() \# start a worker  
        except BaseException,  e:  
            print "异常: ", type(e),  e  
            time.sleep(5)  
            print "maxium i=",  i  
        finally:  
            cond.acquire()  
            cond.notifyAll()  
            cond.release()  
            time.sleep(3)  
            print threading.currentThread().getName(),  " quit"

以下是python2.7在XP下的运行结果，可能跟具体的机器物理配置也有关系。  
...........  
Thread-1021 -- created.  
Thread-1022 -- created. www.2cto.com  
Thread-1023 -- created.  
Thread-1024 -- created.  
Thread-1025 -- created.  
Thread-1026 -- created.  
异常:  <class 'thread.error'> can't start new thread  
Thread-1027 -- created.  
maxium i= 1027  
MainThread  quit

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