HackerRank之Java Datatypes

短命女 2022-04-02 16:56 192阅读 0赞

Java has 8 primitive data types; *char, boolean, byte, short, int, long, float, and double*. For this exercise, we'll work with the primitives used to hold integer values (*byte, short, int,* and *long*):

*  A *byte* is an 8-bit signed integer.
 *  A *short* is a 16-bit signed integer.
 *  An *int* is a 32-bit signed integer.
 *  A *long* is a 64-bit signed integer.

Given an input integer, you must determine which primitive data types are capable of properly storing that input.

To get you started, a portion of the solution is provided for you in the editor.

Answer

import java.util.*;
    import java.io.*;
    
    
    
    class Solution{
        public static void main(String []argh)
        {
    
    
    
            Scanner sc = new Scanner(System.in);
            int t=sc.nextInt();
    
            for(int i=0;i<t;i++)
            {
    
                try
                {
                    long x=sc.nextLong();
                    System.out.println(x+" can be fitted in:");
                    if(x>=-128 && x<=127)
                    {
                        System.out.println("* byte");
                        System.out.println("* short");
                        System.out.println("* int");
                        System.out.println("* long");
                    }
                    else if(x>=-32768 && x<=32767)
                    {
                        System.out.println("* short"); 
                        System.out.println("* int");
                        System.out.println("* long");  
                    }
                    else if(x>=-Math.pow(2,31) && (x<=Math.pow(2,31)-1))
                    {
                        System.out.println("* int");
                        System.out.println("* long");
                    }
                    else if(x>=-Math.pow(2,63) && (x<=Math.pow(2,63)-1))
                    {
                        System.out.println("* long");
                    }
                }
                catch(Exception e)
                {
                    System.out.println(sc.next()+" can't be fitted anywhere.");
                }
    
            }
        }
    }