有a,b两个已按学号升序排序的链表，每个链表中的结点包括学号、成绩。要求把两个链表合并，仍按学号升序排列。...

绝地灬酷狼 2022-04-01 12:12 105阅读 0赞

\#include  < stdio.h >   
\#include  < stdlib.h >   
 \#define  N 10   
typedef  struct  student  
\{  
     int  num;  
     float  score;  
     struct  student  \* next;  
\}STU;  
  
STU  \* create()  
\{  
     int  i;  
    STU  \* p, \* head = NULL, \* tail = head;  
     for  (i = 0 ;i < N;i \++ )  
    \{  
        p = (STU  \* )malloc( sizeof (STU));  
        scanf( " %d%f " , & p \-> num, & p \-> score);  
        p \-> next = NULL;  
         if  (p \-> num < 0 )  
        \{  
            free(p);  
             break ;  
        \}  
         if (head == NULL)  
            head = p;  
         else   
            tail \-> next = p;  
        tail = p;  
    \}  
     return  head;  
\}  
  
 void  output(STU  \* p)  
\{  
     while  (p != NULL)  
    \{  
        printf( " %d\\t%.2f\\n " ,p \-> num,p \-> score);  
        p = p \-> next;  
    \}  
\}  
  
STU  \* link(STU  \* p1,STU  \* p2)  
\{  
    STU  \* p, \* head;  
     if  (p1 \-> num < p2 \-> num)  
    \{  
        head = p = p1;  
        p1 = p1 \-> next;  
    \}  
     else   
    \{  
        head = p = p2;  
        p2 = p2 \-> next;  
    \}  
     while  (p1 != NULL && p2 != NULL)  
    \{  
         if  (p1 \-> num < p2 \-> num)  
        \{  
            p \-> next = p1;  
            p = p1;  
            p1 = p1 \-> next;  
        \}  
         else   
        \{  
            p \-> next = p2;  
            p = p2;  
            p2 = p2 \-> next;  
        \}  
    \}  
     if (p1 != NULL)  
        p \-> next = p1;  
     else   
        p \-> next = p2;  
  
     return  head;  
\}  
  
 int  main( int  argc,  char   \* argv\[\])   
\{  
    STU  \* a, \* b, \* c;  
    printf( " \\n请输入链表a的信息，学号小于零时结束输入：格式(学号 成绩)\\n " );  
    a = create();  
    printf( " \\n请输入链表b的信息，学号小于零时结束输入：格式(学号 成绩)\\n " );  
    b = create();  
    printf( " \\n链表a的信息为：\\n " );  
    output(a);  
    printf( " \\n链表b的信息为：\\n " );  
    output(b);  
    c = link(a,b);  
    printf( " \\n合并后的链表信息为：\\n " );  
    output(c);  
  
     return   0 ;  
\}