H - Oil Deposits

逃离我推掉我的手 2022-03-20 08:08 115阅读 0赞

### 题目描述： ###

The GeoSurvComp geologic survey company is responsible for detecting underground oil deposits. GeoSurvComp works with one large rectangular region of land at a time, and creates a grid that divides the land into numerous square plots. It then analyzes each plot separately, using sensing equipment to determine whether or not the plot contains oil. A plot containing oil is called a pocket. If two pockets are adjacent, then they are part of the same oil deposit. Oil deposits can be quite large and may contain numerous pockets. Your job is to determine how many different oil deposits are contained in a grid.  
Input  
The input contains one or more grids. Each grid begins with a line containing m and n, the number of rows and columns in the grid, separated by a single space. If m = 0 it signals the end of the input; otherwise 1 <= m <= 100 and 1 <= n <= 100. Following this are m lines of n characters each (not counting the end-of-line characters). Each character corresponds to one plot, and is either `*', representing the absence of oil, or`@’, representing an oil pocket.

Output  
are adjacent horizontally, vertically, or diagonally. An oil deposit will not contain more than 100 pockets.  
Sample Input  
1 1  
\*  
3 5  
*@*@\*  
**@**  
*@*@\*  
1 8  
@@\*\*\**@*  
5 5  
\*\*\*\*@  
*@@*@  
*@\*\*@  
@@@*@  
@@\*\*@  
0 0  
Sample Output  
0  
1  
2  
2  
这个题和https://blog.csdn.net/qq\_43506138/article/details/87024481  
这个题是一样的。

#include"stdio.h"
    #include"string.h"
    char Map[100][100];
    int cont;
    int n,k;
    void dfs(int X,int Y)
    {
        int x[8]={-1,-1,-1,0,0,1,1,1};
        int y[8]={-1,0,1,-1,1,-1,0,1};
        for(int i=0;i<8;i++)
        {
            int a=X+x[i];
            int b=Y+y[i];
            if(a>=0&&a<n&&b>=0&&b<k&&Map[a][b]=='@')
            {
                Map[a][b]='*';
                dfs(a,b);
    
            }
        }
    
    }
    int main()
    {
        while(~scanf("%d%d",&n,&k))
        {
            if(n==0)
                break;
            for(int i=0;i<n;i++)
                scanf("%s",Map[i]);
            cont=0;
            for(int i=0;i<n;i++)
            {
               for(int j=0;j<k;j++)
               {
                   if(Map[i][j]=='@')
                   {
                       dfs(i,j);
                       cont++;
                   }
               }
            }
          printf("%d\n",cont);
        }
    }```