Window系统下C/C++程序毫秒和微秒级程序运行时间的获取方法

短命女 2022-03-15 10:42 941阅读 0赞

一、使用clock()函数，获取毫秒级(ms)时间\[1\]

\#include <time.h>//clock()头文件

clock\_t start = clock();

\{statement section\}//测试代码段

clock\_t end = clock();

printf("the running time is :%fs\\n", (double)(end -start)/(double)CLOCKS\_PER\_SEC); //秒

二、基于CPU级的方法，获取微秒级(us)时间\[2,3\]

\#include <stdio.h>  
\#include <windows.h>//头文件

LARGE\_INTEGER nFreq;

LARGE\_INTEGER t1;

LARGE\_INTEGER t2;

double dt;

QueryPerformanceFrequency(&nFreq);  
QueryPerformanceCounter(&t1);

\{statementsection\}//测试代码段  
QueryPerformanceCounter(&t2);  
dt = （t2.QuadPart - t1.QuadPart） / (double)nFreq.QuadPart;  
cout<<"Running time :"<<dt\*1000<<"ms"<<endl;//dt结果乘以1000,将显示时间调整到ms级别显示，乘以1000000，将显示时间调整到us级别显示

备注：可以在代码段添加Sleep()函数测试，如下两个测试实例。

例1：500ms

time\_t start = clock();  
Sleep(1000);//500ms  
time\_t end = clock();  
printf("the running time is :%fms\\n", (double)(end -start));

运行结果，如下：

the running time is :1001.000000ms

例2: 5ms测试

LARGE\_INTEGER nFreq,t1,t2;  
double dt;  
QueryPerformanceFrequency(&nFreq);  
QueryPerformanceCounter(&t1);  
Sleep(5);//5ms,其中1ms=1000us  
QueryPerformanceCounter(&t2);  
dt = (t2.QuadPart - t1.QuadPart)/(double)nFreq.QuadPart;  
cout<<"Running time : "<<dt\*1000000<<"us"<<endl;

运行结果，如下：

Running time : 5162.22us  
\---------------------  
作者：泡泡徐  
来源：CSDN  
原文：https://blog.csdn.net/xpplearnc/article/details/53894048  
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