Java 计算两个时间相差的天，时，分钟，秒

深碍√TFBOYSˉ_ 2022-02-26 20:48 399阅读 0赞

[https://blog.csdn.net/persistencegoing/article/details/84376427][https_blog.csdn.net_persistencegoing_article_details_84376427]

第一种：

public static String getDatePoor(Date endDate, Date nowDate) \{

long nd = 1000 \* 24 \* 60 \* 60;

long nh = 1000 \* 60 \* 60;

long nm = 1000 \* 60;

// long ns = 1000;

// 获得两个时间的毫秒时间差异

long diff = endDate.getTime() - nowDate.getTime();

// 计算差多少天

long day = diff / nd;

// 计算差多少小时

long hour = diff % nd / nh;

// 计算差多少分钟

long min = diff % nd % nh / nm;

// 计算差多少秒//输出结果

// long sec = diff % nd % nh % nm / ns;

return day + "天" + hour + "小时" + min + "分钟";

第二种：

/**
     * 把时间根据时、分、秒转换为时间段
     * @param  str  可选其1值{ "yyyy-MM-dd", "yyyy-MM-dd HH:mm:ss", "yyyy-MM-dd HH:mm", "yyyy/MM/dd", "yyyy/MM/dd HH:mm:ss", "yyyy/MM/dd HH:mm" }
     * @author String ？日前或？小时前或？分钟前？秒前
     */
    public static String getTimes(Object str){
       String resultTimes = "";
       Date now;
       Date date=parseDate(str);
       now = new Date();
       long times = now.getTime() - date.getTime();
       long day = times / (24 * 60 * 60 * 1000);
       long hour = (times / (60 * 60 * 1000) - day * 24);
       long min = ((times / (60 * 1000)) - day * 24 * 60 - hour * 60);
       long sec = (times / 1000 - day * 24 * 60 * 60 - hour * 60 * 60 - min * 60);
       StringBuffer sb = new StringBuffer();
       if(day>0){
          sb.append(day + "天前");
       }else if (hour > 0) {
          sb.append(hour + "小时前");
       } else if (min > 0) {
          sb.append(min + "分钟前");
       } else if (sec >0){
          sb.append(sec + "秒前");
       }else if(times>=0){
          sb.append(times + "毫秒前");
       }else{
          sb.append("超前毫秒数:"+times);
       }
       resultTimes = sb.toString();
        return resultTimes;
    }

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[https_blog.csdn.net_persistencegoing_article_details_84376427]: https://blog.csdn.net/persistencegoing/article/details/84376427