java调用远程接口并接收返回json串

迷南。 2022-02-21 10:15 493阅读 0赞

工具类：

package cn.com.dzqc.util;
    
    import java.io.BufferedReader;
    import java.io.IOException;
    import java.io.InputStreamReader;
    
    import org.apache.http.HttpEntity;
    import org.apache.http.client.methods.CloseableHttpResponse;
    import org.apache.http.client.methods.HttpGet;
    import org.apache.http.impl.client.CloseableHttpClient;
    import org.apache.http.impl.client.HttpClients;
    
    public class HttpClientUtil {
    	 public static String requestByGetMethod(String s) {
    	        CloseableHttpClient httpClient = HttpClients.createDefault();
    	        StringBuilder entityStringBuilder = null;
    	        try {
    	            HttpGet get = new HttpGet(s);
    	            CloseableHttpResponse httpResponse = null;
    	            httpResponse = httpClient.execute(get);
    	            try {
    	                HttpEntity entity = httpResponse.getEntity();
    	                entityStringBuilder = new StringBuilder();
    	                if (null != entity) {
    	                    BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(httpResponse.getEntity().getContent(), "UTF-8"), 8 * 1024);
    	                    String line = null;
    	                    while ((line = bufferedReader.readLine()) != null) {
    	                        entityStringBuilder.append(line + "/n");
    	                    }
    	                }
    	            } finally {
    	                httpResponse.close();
    	            }
    	        } catch (Exception e) {
    	            e.printStackTrace();
    	        } finally {
    	            try {
    	                if (httpClient != null) {
    	                    httpClient.close();
    	                }
    	            } catch (IOException e) {
    	                e.printStackTrace();
    	            }
    	        }
    	        return entityStringBuilder.toString();
    	    }
    
    }

Controller:

@RequestMapping(value="/getjson")
    	@ResponseBody
    	public String getjson(String aa){
    	    String url = "http://127.0.0.1/aaa/aaa/aaa/selectaa"+"?aa="+aa;
                String res = null;
    		try {
    			  res = HttpClientUtil.requestByGetMethod(url);
    	            JSONObject result = new JSONObject();
    	            System.out.println(res);
    	            res = res.substring(res.indexOf("{"), res.indexOf("}") + 1);
    	            System.out.println(res);
    		} catch (Exception e) {
    			// TODO: handle exception
    			e.printStackTrace();
    			
    		}
    		return res;
    	}

这样就可以了

前端ajax

$.ajax({
        				url:"${path}/cost/getjson",
        				type:"post",
        				data: {
        					aa: aa
        				},
        				dataType:'json',  //一定要加上这个，告诉他返回json数据
        				success:function(res){
    						console.log("----")
    						layer.closeAll()
    						if(res.code == 200){ 
    							window.location.href = "www.baidu.com"
    						} else {
    							console.log(res.msg)
    							  layer.open({
    							    content: res.msg
    							    ,btn: '确定'
    							  });
    						}
        				}
        			})