python random.uniform用于随机发红包

偏执的太偏执、 2022-02-04 12:57 341阅读 0赞

一、random.uniform

help(random.uniform)
    Help on method uniform in module random:
    uniform(a, b) method of random.Random instance
        Get a random number in the range [a, b) or [a, b] depending on rounding.

random.uniform用于随机返回指定范围内的浮点数，如下随机返回50-60范围内的浮点数：

random.uniform(50,60)
    55.46093048529164

二、随机发红包流程  
红包的金额cash，  
人员persons,  
一般0.01为最小值，为什么会来说还有最大值，你想假如一个10块的红包6个人抢第一个能抢了9.99，那么第二个人只有剩下0.01，后面的人没得强，这就有问题了。  
所以最大值应该就是红包总金额减去最小值乘以人数(10-0.01x5)，给后面的人每个人都预留0.01，才有得玩。  
代码如下：

#!/usr/bin/env python
    # encoding: utf-8
    """
    @author: wanwei
    @license: (C) Copyright 2013-2017, Node Supply Chain Manager Corporation Limited.
    @contact: wei_wan@sui.com
    @software: pycharm
    @file: random_hongbao.py
    @time: 2019/5/7 19:01
    @desc:
    """
    
    #!/usr/bin/env python
    
    # -*-coding:utf-8 -*-
    
    import random
    
    dic = {}
    persons = ['KeLan', 'Monkey', 'Dexter', 'Superman', 'Iron Man', 'Robin']
    
    
    def redpacket(cash, length, index):
    
        if cash > 0 and length != 1:
            n = round(random.uniform(0.01, cash - (0.01 * (length-1))), 2)
            dic[persons[index]] = n
            print(str(n).ljust(4, "0"))
            length = length - 1
            cash = cash  - n
            index = index + 1
            redpacket(cash, length, index)
        else:
            dic[persons[index]] = round(cash, 2)
            print(str(round(cash, 2)).ljust(4, "0"))
    
    cash = 10.00
    redpacket(cash, len(persons), 0)
    print(dic)
    print("手气最佳:", max(dic.items(), key=lambda x: x[1]))
    print("总红包数之和：", sum(dic.values()))