数据库原理实验四：使用SQL语言进行复杂查询

以你之姓@ 2022-01-21 11:33 257阅读 0赞

**实验目的**

掌握复杂数据查询操作。

**实验内容**

掌握各种连接查询、嵌套查询的使用。

**实验过程（还是使用实验一的表）**

1. 查询每个学生及其选课情况

select student.sno,sname,ssex,sage,sdept,cno,grade
    from student,sc
    where student.sno=sc.sno

2. 查询每门课的间接先修课

select first.cno,second.cpno
    from course first,course second
    where first.cpno=second.cno

3. 将STUDENT,SC进行右连接

select student.sno,sname,ssex,sage,sdept,cno,grade
    from student right outer join sc on student.sno=sc.sno

4. 查询既选修了2号课程又选修了3号课程的学生姓名、学号

select student.sno,sname
    from student inner join sc on student.sno=sc.sno
    where cno='3' and sc.sno in
    (select sno
    from sc
    where cno='2')

5. 查询和刘晨同一年龄的学生

select student.sno,sname
    from student
    where sname!='刘晨' and sage=
    (select sage 
    from student
    where sname='刘晨')

6. 选修了课程名为“数据库”的学生姓名和年龄

select sname,sage
    from student
    where sno in
    (select sno
    from sc
    where cno in
    (select cno
    from course 
    where cname='数据库'))

7. 查询其他系比IS系任一学生年龄小的学生名单

select student.sno,sname
    from student
    where sdept<>'IS' and
    sage<any
    (select sage 
    from student
    where sdept='IS')

8. 查询其他系中比IS系所有学生年龄都小的学生名单

select student.sno,sname
    from student
    where sdept<>'IS' and 
    sage<all
    (select sage 
    from student 
    where sdept='IS')

9. 查询选修了全部课程的学生姓名

select sname
    from student
    where Sno in
    (select Sno from SC
    group by Sno
    having count(*) = (select count(*) from course ))

10. 查询计算机系学生及其性别是男的学生

select student.sno,sname
    from student
    where sdept='IS' and ssex='男'

11. 查询选修课程1的学生集合和选修2号课程学生集合的差集

select sno
    from sc 
    where cno='1' except 
    select sno
    from sc
    where cno='2'

12. 查询李丽同学不学的课程的课程号

select cno
    from course
    where cno not in
    (select cno
    from sc
    where sno in
    (select sno
    from student
    where sname='李丽'))

13. 查询选修了3号课程的学生平均年龄

select avg(sage) as avgsage
    from student inner join sc on student.sno=sc.sno
    where cno='3'

14. 求每门课程学生的平均成绩

select cno,avg(grade) as avggrade
    from sc
    group by cno

15. 统计每门课程的学生选修人数（超过3人的才统计）。要求输出课程号和选修人数，结果按人数降序排列，若人数相同，按课程号升序排列

select course.cno '课程号', count(sc.sno) '人数'
    from course,sc 
    where course.cno=sc.cno 
    group by course.cno 
    having count(sc.sno)>3 
    order by count(sc.sno) desc,course.cno asc

16. 查询学号比刘晨大，而年龄比他小的学生姓名

select sname
    from student
    where sno>(select sno from student where sname='刘晨') 
    and
    sage<(select sage from student where sname='刘晨')

17. 求年龄大于所有女同学年龄的男同学姓名和年龄

select sname,sage
    from student
    where ssex='男' and 
    sage>(select max(sage) from student where ssex='女')

**实验总结**  
1. 分组group by 要用having来限制条件  
2. desc是降序，asc是升序  
3. any（）是任意，all（）是所有