Python加密—AES加密解密

系统管理员 2022-01-15 22:15 472阅读 0赞

[为什么80%的码农都做不了架构师？>>> ][80_] ![hot3.png][]

pycrypto 库： [https://pypi.python.org/pypi/pycrypto/][https_pypi.python.org_pypi_pycrypto]

对业务数据进行AES加密表示成十六进制字符串进行传输。

加密算法参数：

密钥的大小（以位为单位）KeySize = 128

操作块大小（以位为单位）BlockSize = 128

加密模式CipherMode.CBC

填充模式PaddingMode.PKCS7或PaddingMode.PKCS5

注：key与iv为十六进制字符串，长度为32字符，转成字节长度是16字节

加密前业务数据：

code = {
        "key1": "key1",
        "key2": "key2",
        "key3": "key3",
        "key4": "key4",
    }

key = '7A9B48C4960551045B467B89015B528E'
    iv = '787B4DD7A9229B3316A6868F537468D5'

加密代码如下：

import json
    import binascii
    from Crypto.Cipher import AES

BS = 16
    
    def padding(s):
        return s + (BS - len(s) % BS) * chr(BS - len(s) % BS)
    
    key = binascii.unhexlify(key)
    iv = binascii.unhexlify(iv)
    code = json.dumps(code)
    
    obj = AES.new(key, AES.MODE_CBC,  iv)
    cipher_code = obj.encrypt(padding(code))
    aes_code = binascii.hexlify(cipher_code).decode()
    print('加密:', aes_code)

运行结果：

加密: b3eda8d1b762d1784b520a7d11d774d765e2c920b1b996c130d3c3e884e8b16ec431ac98457b2e5e47e5feaf2eadc702e9465534e9abb66ad1bb2135d0a153fbc67dfc6067462db65a390b45818ea734

解密代码如下：

def unpadding(s):
        return s[0:-ord(s[-1])]

s='b3eda8d1b762d1784b520a7d11d774d765e2c920b1b996c130d3c3e884e8b16ec431ac98457b2e5e47e5feaf2eadc702e9465534e9abb66ad1bb2135d0a153fbc67dfc6067462db65a390b45818ea734'

obj = AES.new(key, AES.MODE_CBC,  iv)
    encrypted = obj.decrypt(binascii.unhexlify(s))
    decryption_code = unpadding(encrypted.decode())
    print('解密:', decryption_code)

运行结果：

解密: \{"key4": "key4", "key1": "key1", "key3": "key3", "key2": "key2"\}

注：CBC模式不需要初始向量

转载于:https://my.oschina.net/xxWang/blog/720102

[80_]: https://my.oschina.net/u/2663968/blog/3061647
[hot3.png]: /images/20220115/77e2ad1793f445b697003e5bc8e767bc.png
[https_pypi.python.org_pypi_pycrypto]: https://pypi.python.org/pypi/pycrypto/