POJ 3349, Snowflake Snow Snowflakes

灰太狼 2021-12-22 06:45 132阅读 0赞

hash table

**Description**

You may have heard that no two snowflakes are alike. Your task is to write a program to determine whether this is really true. Your program will read information about a collection of snowflakes, and search for a pair that may be identical. Each snowflake has six arms. For each snowflake, your program will be provided with a measurement of the length of each of the six arms. Any pair of snowflakes which have the same lengths of corresponding arms should be flagged by your program as possibly identical.

**Input**

The first line of input will contain a single integer n, 0 < n ≤ 100000, the number of snowflakes to follow. This will be followed by n lines, each describing a snowflake. Each snowflake will be described by a line containing six integers (each integer is at least 0 and less than 10000000), the lengths of the arms of the snow ake. The lengths of the arms will be given in order around the snowflake (either clockwise or counterclockwise), but they may begin with any of the six arms. For example, the same snowflake could be described as 1 2 3 4 5 6 or 4 3 2 1 6 5.

**Output**

If all of the snowflakes are distinct, your program should print the message:  
No two snowflakes are alike.  
If there is a pair of possibly identical snow akes, your program should print the message:  
Twin snowflakes found.

**Sample Input**  
2  
1 2 3 4 5 6  
4 3 2 1 6 5

**Sample Output**  
Twin snowflakes found.

**Source**  
CCC 2007

--------------------

//  POJ3349.cpp : Defines the entry point for the console application.  
 //  
   
\#include  < iostream >   
 using  namespace  std;  
  
 struct  Snowflake  
\{  
Snowflake():next( 0 )\{\}  
Snowflake \*  next;  
 int  arms\[ 6 \];  
\};  
 bool  compare ( const  Snowflake &  sf1,  const  Snowflake &  sf2)  
\{  
 //  left to right   
  for  ( int  j  =  0 ; j  <  6 ;  \++ j)  
 if  (sf1.arms\[ 0 \]  ==  sf2.arms\[j\])  
\{  
 int  k  =  0 ;  
 for  (; k  <  6 ;  \++ k)  
\{  
 if  (sf1.arms\[k\]  !=  sf2.arms\[(j  \+  k)  %  6 \])  break ;  
\};  
 if  (k  ==  6 )  return  true ;  
\};  
 // right to left   
  for  ( int  j  =  0 ; j  <  6 ;  \++ j)  
 if  (sf1.arms\[ 0 \]  ==  sf2.arms\[j\])  
\{  
 int  k  =  0 ;  
 for  (; k  <  6 ;  \++ k)  
\{  
 if  (sf1.arms\[k\]  !=  sf2.arms\[(j  \-  k  \+  6 )  %  6 \])  break ;  
\};  
 if  (k  ==  6 )  return  true ;  
\};  
 return  false ;  
\}  
  
 int  main( int  argc,  char \*  argv\[\])  
\{  
 int  N;  
scanf( " %d\\n " ,  & N);  
  
 const  int  SIZE  =  33119 ;  
Snowflake hash\[SIZE\];  
memset(hash,  0 ,  sizeof (hash));  
 bool  found  =  false ;  
 for  ( int  i  =  0 ; i  <  N;  \++ i)  
\{  
Snowflake \*  sf  =  new  Snowflake;  
 for  ( int  j  =  0 ; j  <  6 ;  \++ j)scanf( " %d " ,  & sf \-> arms\[j\]);  
 if  (found  ==  false )  
\{  
 int  key  =  sf \-> arms\[ 0 \]  \+  sf \-> arms\[ 1 \]  \+  sf \-> arms\[ 2 \]  \+  sf \-> arms\[ 3 \]  \+  sf \-> arms\[ 4 \]  \+  sf \-> arms\[ 5 \];  
  
Snowflake \*  pt  =  & hash\[key % SIZE\];  
 while ( pt  \-> next  !=  NULL)\{  
pt  =  pt  \-> next;  
 if  (compare( \* pt, \* sf)) found  =  true ;  
\}  
pt \-> next  =  sf;  
\}  
\};  
 if  (found) cout  <<  " Twin snowflakes found.\\n " ;  
 else  cout  <<  " No two snowflakes are alike.\\n " ;  
 return  0 ;  
\}

转载于:https://www.cnblogs.com/asuran/archive/2009/10/08/1578949.html