第三次课后作业

╰+哭是因爲堅強的太久メ 2021-12-20 05:41 318阅读 0赞

学号：2017\*\*\*\*7054

姓名：宋佳殷

第一段：读取文件

def process\_file(dst): \# 读文件到缓冲区  
try: \# 打开文件  
f = open(dst, 'r')  
except IOError as s:  
print (s)  
return None  
try: \# 读文件到缓冲区  
bvffer = f.read()  
  
except:  
print ("Read File Error!")  
return None  
f.close()  
return bvffer

第二段：统计每个单词的频率，存放在字典word\_freq

def process\_buffer(bvffer):  
if bvffer:  
word\_freq = \{\}  
for ch in '“‘!;,.?”':  
\# 下面添加处理缓冲区 bvffer代码，统计每个单词的频率，存放在字典word\_freq  
  
bvffer = bvffer.lower().replace(ch, " ")  
words = bvffer.strip().split()  
for word in words:  
word\_freq\[word\] = word\_freq.get(word, 0) + 1

return word\_freq

第三段：输出 前十 10 的单词

def output\_result(word\_freq):  
if word\_freq:  
sorted\_word\_freq = sorted(word\_freq.items(), key=lambda v: v\[1\], reverse=True)  
for item in sorted\_word\_freq\[:10\]: \# 输出 Top 10 的单词  
print("词:%-5s 频:%-4d " % (item\[0\], item\[1\]))

第四段：主函数

if \_\_name\_\_ == "\_\_main\_\_":  
import argparse  
parser = argparse.ArgumentParser()  
parser.add\_argument('dst')  
args = parser.parse\_args()  
dst = args.dst  
bvffer = process\_file(dst)  
word\_freq = process\_buffer(bvffer)  
output\_result(word\_freq)

执行次数做多的代码

![1628859-20190408181210139-86923553.png][]

执行时间最长的代码

![1628859-20190408181429575-857672827.png][]

前十单词

![1628859-20190408181513435-766120805.png][]

转载于:https://www.cnblogs.com/sjy1999/p/10672314.html

[1628859-20190408181210139-86923553.png]: /images/20211220/3eda20f0fded4fe8b472fad00e24d86e.png
[1628859-20190408181429575-857672827.png]: /images/20211220/90aad853a99b49048fdc8c6fb67f387e.png
[1628859-20190408181513435-766120805.png]: /images/20211220/e3f546cbf0a54a02ac89bd8c3d31fc7f.png