java io流将多个文件写进zip文件

野性酷女 2021-11-08 23:12 306阅读 0赞

public static void main(String[] args) throws Exception {
    		//分别是三个文件的输入流
    		InputStream in1 = new FileInputStream("E:/nomanager/test/file1.txt");
    		InputStream in2 = new FileInputStream("E:/nomanager/test/file2.txt");
    		InputStream in3 = new FileInputStream("E:/nomanager/test/file3.txt");
    		//分别是三个文件读取时的缓冲区大小，1024Bytes,也就是说每次读1M,假如文件1有2.5M,那就要读三次
    		byte[] b1=new byte[1024];
    		byte[] b2=new byte[1024];
    		byte[] b3=new byte[1024];
    		//每个文件读完后，用一个字符串存储文件内容
    		String s1="";
    		String s2="";
    		String s3="";
    		
    		//下面这个while循环读文件的代码不知道你看不看得懂，我不知道该怎么写注释，你要是不懂再问我吧
    		int len1=0;
    		int len2=0;
    		int len3=0;
    		while((len1=in1.read(b1))!=-1){
    			s1+=new String(b1, 0, len1);
    		}
    		while((len2=in2.read(b2))!=-1){
    			s2+=new String(b2, 0, len2);
    		}
    		while((len3=in3.read(b3))!=-1){
    			s3+=new String(b3, 0, len3);
    		}
    		
    		
    		
    		
    		//定义输出流，目的地是aaa.zip
    		FileOutputStream fout = new FileOutputStream("E:/nomanager/test/aaa.zip");
    		//将三个文件的内容放进一个map里
    		Map<String, byte[]> datas = new HashMap<String, byte[]>();
    		datas.put("file1.txt", s1.getBytes());
    		datas.put("file2.txt", s2.getBytes());
    		datas.put("file3.txt", s3.getBytes());
    
    		//装饰器模式：用ZipOutputStream包装输出流，使其拥有写入zip文件的能力
    		ZipOutputStream zipout = new ZipOutputStream(new BufferedOutputStream(fout));
    		
    		//遍历
    		Set<String> keys = datas.keySet();
    		for (String key : keys) {
    			//下面就是循环把每个文件写进zip文件
    			InputStream bin = new BufferedInputStream(new ByteArrayInputStream(datas.get(key)));
    			byte[] b = new byte[1024];
    			
    			zipout.putNextEntry(new ZipEntry(key));
    			int len = -1;
    			while ((len = bin.read(b)) !=-1) {
    				zipout.write(b, 0, len);
    			}
    		}
    		
    		
    		zipout.close();
    		
    		
    	}