java io流将多个文件写进zip文件-向日葵屋

java io流将多个文件写进zip文件

野性酷女 2021-11-08 23:12 353阅读 0赞

public static void main(String[] args) throws Exception {
        //分别是三个文件的输入流
        InputStream in1 = new FileInputStream("E:/nomanager/test/file1.txt");
        InputStream in2 = new FileInputStream("E:/nomanager/test/file2.txt");
        InputStream in3 = new FileInputStream("E:/nomanager/test/file3.txt");
        //分别是三个文件读取时的缓冲区大小，1024Bytes,也就是说每次读1M,假如文件1有2.5M,那就要读三次
        byte[] b1=new byte[1024];
        byte[] b2=new byte[1024];
        byte[] b3=new byte[1024];
        //每个文件读完后，用一个字符串存储文件内容
        String s1="";
        String s2="";
        String s3="";
        //下面这个while循环读文件的代码不知道你看不看得懂，我不知道该怎么写注释，你要是不懂再问我吧
        int len1=0;
        int len2=0;
        int len3=0;
        while((len1=in1.read(b1))!=-1){
            s1+=new String(b1, 0, len1);
        }
        while((len2=in2.read(b2))!=-1){
            s2+=new String(b2, 0, len2);
        }
        while((len3=in3.read(b3))!=-1){
            s3+=new String(b3, 0, len3);
        }
        //定义输出流，目的地是aaa.zip
        FileOutputStream fout = new FileOutputStream("E:/nomanager/test/aaa.zip");
        //将三个文件的内容放进一个map里
        Map<String, byte[]> datas = new HashMap<String, byte[]>();
        datas.put("file1.txt", s1.getBytes());
        datas.put("file2.txt", s2.getBytes());
        datas.put("file3.txt", s3.getBytes());
        //装饰器模式：用ZipOutputStream包装输出流，使其拥有写入zip文件的能力
        ZipOutputStream zipout = new ZipOutputStream(new BufferedOutputStream(fout));
        //遍历
        Set<String> keys = datas.keySet();
        for (String key : keys) {
            //下面就是循环把每个文件写进zip文件
            InputStream bin = new BufferedInputStream(new ByteArrayInputStream(datas.get(key)));
            byte[] b = new byte[1024];
            zipout.putNextEntry(new ZipEntry(key));
            int len = -1;
            while ((len = bin.read(b)) !=-1) {
                zipout.write(b, 0, len);
            }
        }
        zipout.close();
    }