java 通过正则表达式把字符串 xml 标签中的内容截取出来

￡神魔★判官ぃ 2021-11-02 04:42 1344阅读 0赞

**废话不多说，直接上代码：**

package self.learn.pratice;
    
    import java.text.ParseException;
    import java.util.ArrayList;
    import java.util.List;
    import java.util.regex.*;
    public class ssss { 
    	
    	public static void main(String[] args) throws ParseException { 
    		// inXml 为要截取的字符串
    		String inXml = "<SOAP-ENV:Envelope xmlns:SOAP-ENV=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:SOAP-ENC=\"http://schemas.xmlsoap.org/soap/encoding/\" xmlns:xsi=\"http://www.w3.org/2001/XMLSchema-instance\" xmlns:xsd=\"http://www.w3.org/2001/XMLSchema\" xmlns:ns6=\"http://www.chinatelecom.com/spr/\">"
    					+" <SOAP-ENV:Body>"
    					+" <ns6:User_Info_Response>"
    					+" <IsSuccess>0</IsSuccess>"
    					+" <ErrorDesc>success</ErrorDesc>"
    					+" </ns6:User_Info_Response>"
    					+" </SOAP-ENV:Body>"
    					+" </SOAP-ENV:Envelope>";
    		
    		String context = null;
    		// 截取<ErrorDesc> </ErrorDesc> 标签中的内容
    		String xml = "ErrorDesc";
    		context = regexLabel(inXml,"ErrorDesc");
    		System.out.println(context);
    		}
    
    	// 截取内容的函数
    	public static String regexLabel(String xml,String label) { 
    		String context = "";
    		//正则表达式 
    		String regex = "<"+label+">(.*?)</"+label+">";
    		        Pattern pattern = Pattern.compile(regex);
    		        Matcher m = pattern.matcher(xml);
    		        List<String> list = new ArrayList<String>();		       		
    		        while(m.find()){ 
    			    int i = 1;
    			    list.add(m.group(i));
    			    i++;			    
    		        }
    		        if(list.size() > 0){ 
    		        	context = list.get(0);
    		        }
    		        return context;		
    		}
    }

运行结果截图：  
![在这里插入图片描述][2019081009164175.png]

[2019081009164175.png]: /images/20211102/67595aef914040e38d940116607f3ca6.png