MySQL获取某个时间范围内的数据 TO_DAYS(date)函数

旧城等待， 2021-11-01 13:32 461阅读 0赞

1、利用to\_days函数查询今天的数据：

select \* from 表名 where to\_days(时间字段名) = to\_days(now());

to\_days函数：返回从0000年（公元1年）至当前日期的总天数。  
2、昨天  
SELECT \* FROM 表名 WHERE TO\_DAYS( NOW( ) ) – TO\_DAYS( 时间字段名) <= 1  
3.7天  
SELECT \* FROM 表名 where DATE\_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)  
4.近30天  
SELECT \* FROM 表名 where DATE\_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)  
5.本月  
SELECT \* FROM 表名 WHERE DATE\_FORMAT( 时间字段名, ‘%Y%m' ) = DATE\_FORMAT( CURDATE( ) , ‘%Y%m' )  
6.上一月  
SELECT \* FROM 表名 WHERE PERIOD\_DIFF( date\_format( now( ) , ‘%Y%m' ) , date\_format( 时间字段名, ‘%Y%m' ) ) =1  
\#查询本季度数据  
select \* from \`ht\_invoice\_information\` where QUARTER(create\_date)=QUARTER(now());  
\#查询上季度数据  
select \* from \`ht\_invoice\_information\` where QUARTER(create\_date)=QUARTER(DATE\_SUB(now(),interval 1 QUARTER));  
\#查询本年数据  
select \* from \`ht\_invoice\_information\` where YEAR(create\_date)=YEAR(NOW());  
\#查询上年数据  
select \* from \`ht\_invoice\_information\` where year(create\_date)=year(date\_sub(now(),interval 1 year));  
  
查询当前这周的数据  
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date\_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());  
查询上周的数据  
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date\_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;  
查询当前月份的数据  
select name,submittime from enterprise where date\_format(submittime,'%Y-%m')=date\_format(now(),'%Y-%m')  
查询距离当前现在6个月的数据  
select name,submittime from enterprise where submittime between date\_sub(now(),interval 6 month) and now();  
查询上个月的数据  
select name,submittime from enterprise where date\_format(submittime,'%Y-%m')=date\_format(DATE\_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')  
select \* from \` user \` where DATE\_FORMAT(pudate, ‘ %Y%m ‘ ) = DATE\_FORMAT(CURDATE(), ‘ %Y%m ‘ ) ;  
select \* from user where WEEKOFYEAR(FROM\_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())  
select \*  
from user  
where MONTH (FROM\_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())  
select \*  
from \[ user \]  
where YEAR (FROM\_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = YEAR (now())  
and MONTH (FROM\_UNIXTIME(pudate, ‘ %y-%m-%d ‘ )) = MONTH (now())  
select \*  
from \[ user \]  
where pudate between 上月最后一天  
and 下月第一天  
where date(regdate) = curdate();  
select \* from test where year(regdate)=year(now()) and month(regdate)=month(now()) and day(regdate)=day(now())  
SELECT date( c\_instime ) ,curdate( )  
FROM \`t\_score\`  
WHERE 1  
LIMIT 0 , 30

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分享自[https://www.cnblogs.com/qcxdoit/p/7085799.html][https_www.cnblogs.com_qcxdoit_p_7085799.html]

转载于:https://www.cnblogs.com/anenyang/p/11188750.html

[https_www.cnblogs.com_qcxdoit_p_7085799.html]: https://www.cnblogs.com/qcxdoit/p/7085799.html