Listview简单demo

亦凉 2021-05-03 09:42 611阅读 0赞

最外层 activity\_main.xml

listview的每一个子项的内容布局 listviewitem.xml

strings.xml

<?xml version="1.0" encoding="utf-8"?>
    <resources>
    
        <string name="app_name">ListViewDemo</string>
        <string name="action_settings">Settings</string>
        <string-array name="roles">
            <item>宋江</item>
            <item>武松</item>
            <item>鲁智深</item>
            <item>林冲</item>
            <item>卢俊义</item>
            <item>李逵</item>
            <item>柴进 </item>
            <item>吴用</item>
            <item>秦明 </item>
            <item>朱仝</item>
        </string-array>
        <string-array name="cnames">
            <item>及时雨</item>
            <item>行者</item>
            <item>花和尚</item>
            <item>豹子头</item>
            <item>玉麒麟</item>
            <item>黑旋风</item>
            <item>小旋风 </item>
            <item>智多星</item>
            <item>霹雳火 </item>
            <item>美髯公</item>
        </string-array>
    
    </resources>

MainActivity.java

public class MainActivity extends ActionBarActivity { 
    
        @Override
        protected void onCreate(Bundle savedInstanceState) {
            super.onCreate(savedInstanceState);
            setContentView(R.layout.activity_main);
            ListView lv = (ListView)findViewById(R.id.listView1);
            //获取资源文件中的数组
            final String[] roles = getResources().getStringArray(R.array.roles);
            final String[] cnames = getResources().getStringArray(R.array.cnames);
            //构造数据集合
            Map<String,Object> item;
            List<Map<String,Object>> data = new ArrayList<Map<String,Object>>();
            for (int i =0 ;i<roles.length;i++) {
                item = new HashMap<String,Object>();
                item.put("img", R.drawable.role00+i);   //***
                item.put("name", roles[i]);
                item.put("cname",cnames[i]);
                data.add(item);
            }
            //创建适配器
            SimpleAdapter sa = new SimpleAdapter(this,data,R.layout.listviewitem,
                    new String[]{
       "img","name","cname"},
                    new int[]{R.id.listview_item_img,R.id.listview_item_name,R.id.listview_item_nickname});
            lv.setAdapter(sa);
        }
    }

对img赋值时采用R.drawable.role00+i的形式，原因是图片资源的命名都是连续的