利用if语句求解成绩等级问题

左手的ㄟ右手 2024-03-31 18:04 78阅读 0赞

**1** **问题**

![65ada959c2527552102a1a577e895ee0.png][]

成绩进行划分等级，人工划分容易出错，且数量庞大。

**2** **方法**

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 <td><img alt="32fc9bd5fce1ec68f27d0780e4cbda79.png" src="https://img-blog.csdnimg.cn/img_convert/32fc9bd5fce1ec68f27d0780e4cbda79.png"> public class Text06 { &nbsp; &nbsp;public static void main(String[] args) { &nbsp; &nbsp; &nbsp; &nbsp;int score=100; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("score"); &nbsp; &nbsp; &nbsp; &nbsp;// 1.成绩大于等于85 &nbsp; &nbsp; &nbsp; &nbsp;if (score&gt;=85){ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("A"); &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp; &nbsp; &nbsp;//2.成绩在70到85之间（包含70） &nbsp; &nbsp; &nbsp; &nbsp;else if (score&gt;=70&amp;&amp;score&lt;85){ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("B"); &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp; &nbsp; &nbsp;//3.成绩在60到70之间（包含60） &nbsp; &nbsp; &nbsp; &nbsp;else if (score&gt;=60&amp;&amp;score&lt;70){ &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("C"); &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp; &nbsp; &nbsp;//4.成绩在60分以下 &nbsp; &nbsp; &nbsp; &nbsp; else { &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp;System.out.println("D"); &nbsp; &nbsp; &nbsp; &nbsp;} &nbsp; &nbsp;} }</td> 
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**3** **结语**

针对成绩等级问题，提出使用Java相关代码的方法，通过利用if语句，证明该方法是有效的，该方法在判断过程中快捷有效，并且不容易出错，在生活中也常用。

[65ada959c2527552102a1a577e895ee0.png]: https://image.dandelioncloud.cn/pgy_files/images/2024/03/31/1b039905bd3a48b78b701c65c8af49cf.png