用Java语言统计一篇英文短文

布满荆棘的人生 2024-04-03 08:22 40阅读 0赞

设有英文短文，请编写代码实现：

\*1 统计以字母 w 开头的单词数；

\*2 统计单词中含“or”字符串的单词数；

\*3 统计长度为 3 的单词数。

\*4 统计有多少单词。

Last fall I walked with a friend in hometown. He was recognized as the most stupid among my childhood playmates, but he has now been Number One in an enterprise. When we came to a fork, a blind man walked from another direction. Testing the road with his bamboo pole, the blind man was walking very slowly towards the road we were going to. I chatted with my friend as we were walking. I talked about my five job-hoppings within two years and the experiences I was still struggling in the plight now. My friend nodded and smiled, but he kept silent all along. After a while, I occasionally looked back and found the blind man had vanished.

for方法：

package com.me;
    
    import java.util.Scanner;
    
    public class Danci1 {
    
    	public static void main(String[] args) {
    		// TODO 自动生成的方法存根
                   @SuppressWarnings("resource")  //批注允许选择性地取消特定代码段(即类或方法)中的警告
    			Scanner scan =new Scanner(System.in);
                   System.out.println("请输入文章：");  //提示用户输入
                   String src = scan.nextLine();    //等待用户在命令行输入一行文本回车
                   String[] wordList = src.split(" ");  //根据空格将字符串s分割成字符串数组
                   
                   int count = wordList.length; //将字符串数组分割成多少部分的值赋给count,从而得到有多少个单词
                   System.out.printf("总共单词量为；%d个\n",count);
                   
                   int w = 0, or =0, three = 0;
                   for(String word : wordList) {
                	   if(word.startsWith("w")) {
                		   w++;
                	   }
                	   if(word.contains("or")) {
                		   or++;
                	   }
                	   if(word.length() == 3) {
                		   three++;
                	   }
                   }
                   System.out.printf("w开头的单词有：%d 个\n",w);
                   System.out.printf("包含or的单词有：%d 个\n",or);
                   System.out.printf("长度为3的单词有：%d 个\n",three);
    	}
    
    }

运行效果：

![cfa1c64e487843e2ba452b11d80efcdd.png][]

do...while方法：

package com.me;
    
    import java.util.Scanner;
    import java.util.StringTokenizer;
    
    public class Danci2 {
    
    	public static void main(String[] args) {
    		// TODO 自动生成的方法存根
    		 @SuppressWarnings("resource")  //批注允许选择性地取消特定代码段(即类或方法)中的警告
    			Scanner sc =new Scanner(System.in);
                System.out.println("请输入文章：");  //提示用户输入
                String s = sc.nextLine();    //等待用户在命令行输入一行文本回车
                StringTokenizer st = new StringTokenizer(s," "); //根据空格将字符串s,且显示空格
                
                int numble = st.countTokens(); //将字符串数组分割成多少部分的值赋给numble,从而得到有多少个单词
                System.out.printf("单词个数为；%d个\n",+numble);
                
                int fircount = 0, seccount =0, thicount = 0;
                int i =0;
                String str[]=s.split(" "); //根据空格把字符串s分割成字符数组
                do {
                	if(str[i].charAt(0)=='w') {
                		fircount++;
                	}
                	if(str[i].contains("or")) {
                		seccount++;
                	}
                	if(str[i].length()==3) {
                		thicount++;
                	}
                	i++;
                }
                while(i<str.length);
                System.out.printf("w开头的单词有：%d 个\n",+fircount);
                System.out.printf("包含or的单词有：%d 个\n",+seccount);
                System.out.printf("长度为3的单词有：%d 个\n",+thicount);
    	}
    
    }

运行效果：

![841b8e43d51246bd8165941dfa113259.png][]

[cfa1c64e487843e2ba452b11d80efcdd.png]: https://image.dandelioncloud.cn/pgy_files/images/2024/04/03/9e7928503a7f42808ebb8ee93bc518b2.png
[841b8e43d51246bd8165941dfa113259.png]: https://image.dandelioncloud.cn/pgy_files/images/2024/04/03/e802e02fffe545a589fd84315ee65ffb.png